What is the solution for y^{''}+y+x=0,y(0)=0,y^'(1)=0 ?

The solution for y^{''}+y+x=0,y(0)=0,y^'(1)=0 is y=-x+(sin(x))/(cos(1))

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y^{''}+y+x=0,y(0)=0,y^'(1)=0

y^{^{''}} + y + x = 0, y (0) = 0, y^{^{'}} (1) = 0

y = - x + \frac{sin ( x )}{cos ( 1 )}

Solution steps

y^{''} (x) + y + x = 0

Solve linear ODE:

y = - x + \frac{sin ( x )}{cos ( 1 )}

y = - x + \frac{sin ( x )}{cos ( 1 )}

What is the solution for y^{''}+y+x=0,y(0)=0,y^'(1)=0 ?
The solution for y^{''}+y+x=0,y(0)=0,y^'(1)=0 is y=-x+(sin(x))/(cos(1))