What is the integral of 2cos(x)sin^2(x) ?

The integral of 2cos(x)sin^2(x) is 2/3 sin^3(x)+C

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integral of 2cos(x)sin^2(x)

\int 2 cos (x) sin^{2} (x) d x

\frac{2}{3} sin^{3} (x) + C

Solution steps

\int 2 cos (x) sin^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int cos (x) sin^{2} (x) d x

Apply u-substitution

= 2 \cdot \int u^{2} d u

Apply the Power Rule

= 2 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= 2 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

2 \cdot \frac{sin ^{3} ( x )}{3} : \frac{2}{3} sin^{3} (x)

= \frac{2}{3} sin^{3} (x)

Add a constant to the solution

= \frac{2}{3} sin^{3} (x) + C

What is the integral of 2cos(x)sin^2(x) ?
The integral of 2cos(x)sin^2(x) is 2/3 sin^3(x)+C