What is the derivative of arccos(4/x) ?

The derivative of arccos(4/x) is 4/(xsqrt(x^2-16))

What is the first derivative of arccos(4/x) ?

The first derivative of arccos(4/x) is 4/(xsqrt(x^2-16))

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\frac{d}{d x} (arccos (\frac{4}{x}))

\frac{4}{x x ^{2} - 16}

Solution steps

\frac{d}{d x} (arccos (\frac{4}{x}))

Apply the chain rule:

- \frac{1}{1 - ( \frac{4}{x} ) ^{2}} \frac{d}{d x} (\frac{4}{x})

= - \frac{1}{1 - ( \frac{4}{x} ) ^{2}} \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= - \frac{1}{1 - ( \frac{4}{x} ) ^{2}} (- \frac{4}{x ^{2}})

Simplify

- \frac{1}{1 - ( \frac{4}{x} ) ^{2}} (- \frac{4}{x ^{2}}) : \frac{4}{x x ^{2} - 16}

= \frac{4}{x x ^{2} - 16}

What is the derivative of arccos(4/x) ?
The derivative of arccos(4/x) is 4/(xsqrt(x^2-16))
What is the first derivative of arccos(4/x) ?
The first derivative of arccos(4/x) is 4/(xsqrt(x^2-16))