What is the derivative of f(t)=-3t^2+2t-4 ?

The derivative of f(t)=-3t^2+2t-4 is -6t+2

What is the first derivative of f(t)=-3t^2+2t-4 ?

The first derivative of f(t)=-3t^2+2t-4 is -6t+2

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derivative of

f (t) = - 3 t^{2} + 2 t - 4

- 6 t + 2

Solution steps

\frac{d}{d t} (- 3 t^{2} + 2 t - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (3 t^{2}) + \frac{d}{d t} (2 t) - \frac{d}{d t} (4)

\frac{d}{d t} (3 t^{2}) = 6 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (4) = 0

= - 6 t + 2 - 0

Simplify

= - 6 t + 2

What is the derivative of f(t)=-3t^2+2t-4 ?
The derivative of f(t)=-3t^2+2t-4 is -6t+2
What is the first derivative of f(t)=-3t^2+2t-4 ?
The first derivative of f(t)=-3t^2+2t-4 is -6t+2