What is (\partial)/(\partial z)(2x-3yz) ?

The answer to (\partial)/(\partial z)(2x-3yz) is -3y

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(\partial)/(\partial z)(2x-3yz)

\frac{\partial}{\partial z} (2 x - 3 yz)

- 3 y

Solution steps

\frac{\partial}{\partial z} (2 x - 3 yz)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (2 x) - \frac{\partial}{\partial z} (3 yz)

\frac{\partial}{\partial z} (2 x) = 0

\frac{\partial}{\partial z} (3 yz) = 3 y

= 0 - 3 y

Simplify

= - 3 y

What is (\partial)/(\partial z)(2x-3yz) ?
The answer to (\partial)/(\partial z)(2x-3yz) is -3y