What is the derivative of y=(3x-7)/(2x+4) ?

The derivative of y=(3x-7)/(2x+4) is (13)/(2(x+2)^2)

What is the first derivative of y=(3x-7)/(2x+4) ?

The first derivative of y=(3x-7)/(2x+4) is (13)/(2(x+2)^2)

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derivative of

y = \frac{3 x - 7}{2 x + 4}

\frac{13}{2 ( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x - 7}{2 x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 7 ) ( 2 x + 4 ) - \frac{d}{d x} ( 2 x + 4 ) ( 3 x - 7 )}{( 2 x + 4 ) ^{2}}

\frac{d}{d x} (3 x - 7) = 3

\frac{d}{d x} (2 x + 4) = 2

= \frac{3 ( 2 x + 4 ) - 2 ( 3 x - 7 )}{( 2 x + 4 ) ^{2}}

Simplify

\frac{3 ( 2 x + 4 ) - 2 ( 3 x - 7 )}{( 2 x + 4 ) ^{2}} : \frac{13}{2 ( x + 2 ) ^{2}}

= \frac{13}{2 ( x + 2 ) ^{2}}

What is the derivative of y=(3x-7)/(2x+4) ?
The derivative of y=(3x-7)/(2x+4) is (13)/(2(x+2)^2)
What is the first derivative of y=(3x-7)/(2x+4) ?
The first derivative of y=(3x-7)/(2x+4) is (13)/(2(x+2)^2)