What is the integral of \sqrt[3]{x-1} ?

The integral of \sqrt[3]{x-1} is 3/4 (x-1)^{4/3}+C

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integral of \sqrt[3]{x-1}

\frac{3}{4} (x - 1)^{\frac{4}{3}} + C

Solution steps

Apply u-substitution

Apply the Power Rule

= \frac{3}{4} u^{\frac{4}{3}}

Substitute back

u = x - 1

= \frac{3}{4} (x - 1)^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} (x - 1)^{\frac{4}{3}} + C

What is the integral of \sqrt[3]{x-1} ?
The integral of \sqrt[3]{x-1} is 3/4 (x-1)^{4/3}+C