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Popular Calculus >

taylor f(x)=x^2-2x+4

Solution

taylor

f (x) = x^{2} - 2 x + 4

Solution

4 - 2 x + x^{2}

Solution steps

Apply the Taylor Formula

= 4 + \frac{\frac{d}{d x} ( x ^{2} - 2 x + 4 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} - 2 x + 4 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} - 2 x + 4 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 4 + \frac{- 2}{1 !} x + \frac{2}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= 4 - 2 x + x^{2}

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Frequently Asked Questions (FAQ)

What is taylor f(x)=x^2-2x+4 ?
The answer to taylor f(x)=x^2-2x+4 is 4-2x+x^2