What is the derivative of 7/((x+1^2)) ?

The derivative of 7/((x+1^2)) is -(14)/((x+1)^3)

What is the first derivative of 7/((x+1^2)) ?

The first derivative of 7/((x+1^2)) is -(14)/((x+1)^3)

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\frac{d}{d x} (\frac{7}{( x + 1 ) ^{2}})

- \frac{14}{( x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{7}{( x + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{( x + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((x + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 1 ) ^{3}} \frac{d}{d x} (x + 1)

= - \frac{2}{( x + 1 ) ^{3}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 7 (- \frac{2}{( x + 1 ) ^{3}} \cdot 1)

Simplify

7 (- \frac{2}{( x + 1 ) ^{3}} \cdot 1) : - \frac{14}{( x + 1 ) ^{3}}

= - \frac{14}{( x + 1 ) ^{3}}

What is the derivative of 7/((x+1^2)) ?
The derivative of 7/((x+1^2)) is -(14)/((x+1)^3)
What is the first derivative of 7/((x+1^2)) ?
The first derivative of 7/((x+1^2)) is -(14)/((x+1)^3)