What is the derivative of x^5+3x^2+1 ?

The derivative of x^5+3x^2+1 is 5x^4+6x

What is the first derivative of x^5+3x^2+1 ?

The first derivative of x^5+3x^2+1 is 5x^4+6x

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\frac{d}{d x} (x^{5} + 3 x^{2} + 1)

5 x^{4} + 6 x

Solution steps

\frac{d}{d x} (x^{5} + 3 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 5 x^{4} + 6 x + 0

Simplify

= 5 x^{4} + 6 x

What is the derivative of x^5+3x^2+1 ?
The derivative of x^5+3x^2+1 is 5x^4+6x
What is the first derivative of x^5+3x^2+1 ?
The first derivative of x^5+3x^2+1 is 5x^4+6x