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Popular Calculus >

integral from-1 to 0 of 2-e^{-x}

Solution

\int_{- 1}^{0} 2 - e^{- x} d x

Solution

- e + 3

+1

Decimal

0.28171 \dots

Solution steps

\int_{- 1}^{0} 2 - e^{- x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 2 d x - \int_{- 1}^{0} e^{- x} d x

\int_{- 1}^{0} 2 d x = 2

\int_{- 1}^{0} e^{- x} d x = e - 1

= 2 - (e - 1)

Simplify

= - e + 3

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of 2-e^{-x} ?
The integral from-1 to 0 of 2-e^{-x} is -e+3