What is the tangent of y=-e^{-x-2},(-3,-e) ?

The tangent of y=-e^{-x-2},(-3,-e) is y=ex+2e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=-e^{-x-2},(-3,-e)

tangent of

y = - e^{- x - 2}, (- 3, - e)

y = e x + 2 e

Solution steps

Find the slope of

y = - e^{- x - 2} : \frac{d y}{d x} = e^{- x - 2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = e

Find the line with slope m=

e

and passing through

(- 3, - e) : y = e x + 2 e

y = e x + 2 e

What is the tangent of y=-e^{-x-2},(-3,-e) ?
The tangent of y=-e^{-x-2},(-3,-e) is y=ex+2e