What is the integral of (sqrt(x^2))/x ?

The integral of (sqrt(x^2))/x is x+C

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integral of (sqrt(x^2))/x

\int \frac{x ^{2}}{x} d x

x + C

Solution steps

\int \frac{x ^{2}}{x} d x

x^{2} = (x),

assuming

x \geq 0

= \int \frac{x}{x} d x

Simplify

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C