What is the integral of (y^{3/2})^2 ?

The integral of (y^{3/2})^2 is (y^4)/4+C

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integral of (y^{3/2})^2

\int (y^{\frac{3}{2}})^{2} d y

\frac{y ^{4}}{4} + C

Solution steps

\int (y^{\frac{3}{2}})^{2} d y

Simplify

(y^{\frac{3}{2}})^{2} : y^{3}

= \int y^{3} d y

Apply the Power Rule

= \frac{y ^{4}}{4}

Add a constant to the solution

= \frac{y ^{4}}{4} + C