What is (\partial)/(\partial x)(-9e^xcos(yz)) ?

The answer to (\partial)/(\partial x)(-9e^xcos(yz)) is -9cos(yz)e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(-9e^xcos(yz))

\frac{\partial}{\partial x} (- 9 e^{x} cos (yz))

- 9 cos (yz) e^{x}

Solution steps

\frac{\partial}{\partial x} (- 9 e^{x} cos (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 cos (yz) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - 9 cos (yz) e^{x}

What is (\partial)/(\partial x)(-9e^xcos(yz)) ?
The answer to (\partial)/(\partial x)(-9e^xcos(yz)) is -9cos(yz)e^x