What is the tangent of f(x)=x^2+3x-3,\at x=1 ?

The tangent of f(x)=x^2+3x-3,\at x=1 is y=5x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=x^2+3x-3,\at x=1

tangent of

f (x) = x^{2} + 3 x - 3, at x = 1

y = 5 x - 4

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = x^{2} + 3 x - 3 : \frac{df ( x )}{d x} = 2 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 1) : y = 5 x - 4

y = 5 x - 4

What is the tangent of f(x)=x^2+3x-3,\at x=1 ?
The tangent of f(x)=x^2+3x-3,\at x=1 is y=5x-4