What is the integral of 4/(x^5)-3/(x^4) ?

The integral of 4/(x^5)-3/(x^4) is -1/(x^4)+1/(x^3)+C

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integral of 4/(x^5)-3/(x^4)

\int \frac{4}{x ^{5}} - \frac{3}{x ^{4}} d x

- \frac{1}{x ^{4}} + \frac{1}{x ^{3}} + C

Solution steps

\int \frac{4}{x ^{5}} - \frac{3}{x ^{4}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{x ^{5}} d x - \int \frac{3}{x ^{4}} d x

\int \frac{4}{x ^{5}} d x = - \frac{1}{x ^{4}}

\int \frac{3}{x ^{4}} d x = - \frac{1}{x ^{3}}

= - \frac{1}{x ^{4}} - (- \frac{1}{x ^{3}})

Simplify

= - \frac{1}{x ^{4}} + \frac{1}{x ^{3}}

Add a constant to the solution

= - \frac{1}{x ^{4}} + \frac{1}{x ^{3}} + C

What is the integral of 4/(x^5)-3/(x^4) ?
The integral of 4/(x^5)-3/(x^4) is -1/(x^4)+1/(x^3)+C