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人気のある微分積分 >

integral from-4 to 6 of [f(x)+2]

解

\int_{- 4}^{6} [f (x) + 2] d x

解

20 + f \cdot 10

解答ステップ

\int_{- 4}^{6} f x + 2 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{6} 2 d x + \int_{- 4}^{6} f x d x

\int_{- 4}^{6} 2 d x = 20

\int_{- 4}^{6} f x d x = f \cdot 10

= 20 + f \cdot 10

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