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人気のある微分積分 >

(\partial)/(\partial y)(y^2+1)

解

\frac{\partial}{\partial y} (y^{2} + 1)

解

2 y

解答ステップ

\frac{\partial}{\partial y} (y^{2} + 1)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (1) = 0

= 2 y + 0

簡素化

= 2 y

人気の例

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y^{^{''}} + 2 y^{^{'}} + y = 2 e^{- t}, y (0) = - 1, y^{^{'}} (0) = 3

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