What is the derivative of (x^2/4+2x+3) ?

The derivative of (x^2/4+2x+3) is x/2+2

What is the first derivative of (x^2/4+2x+3) ?

The first derivative of (x^2/4+2x+3) is x/2+2

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\frac{d}{d x} (\frac{x ^{2}}{4} + 2 x + 3)

\frac{x}{2} + 2

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{4} + 2 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{4}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (3)

\frac{d}{d x} (\frac{x ^{2}}{4}) = \frac{x}{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= \frac{x}{2} + 2 + 0

Simplify

= \frac{x}{2} + 2

What is the derivative of (x^2/4+2x+3) ?
The derivative of (x^2/4+2x+3) is x/2+2
What is the first derivative of (x^2/4+2x+3) ?
The first derivative of (x^2/4+2x+3) is x/2+2