derivative of (x^2/4+2x+3)

解

\frac{d}{d x} (\frac{x ^{2}}{4} + 2 x + 3)

\frac{x}{2} + 2

解答ステップ

\frac{d}{d x} (\frac{x ^{2}}{4} + 2 x + 3)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{4}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (3)

\frac{d}{d x} (\frac{x ^{2}}{4}) = \frac{x}{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= \frac{x}{2} + 2 + 0

簡素化

= \frac{x}{2} + 2