What is the limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 ?

The limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 is (e^{e^{e^{e^x}}-2})/2

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limit as e^{e^x} approaches 0+of (e^{e^x-2})/2

e^{e^{e^{e^{x}}}} \to 0 + lim \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

\frac{e ^{e^{e^{e^{x}}} - 2}}{2}

Solution steps

e^{e^{e^{e^{x}}}} \to 0 + lim \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

x \to a lim c = c

= \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

What is the limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 ?
The limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 is (e^{e^{e^{e^x}}-2})/2