What is implicit (dy)/(dx),y=arccos(4x^2) ?

The answer to implicit (dy)/(dx),y=arccos(4x^2) is (dy)/(dx)=-(8x)/(sqrt(1-16x^4))

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implicit (dy)/(dx),y=arccos(4x^2)

implicit derivative

\frac{d y}{d x}, y = arccos (4 x^{2})

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

Solution steps

y = arccos (4 x^{2})

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

What is implicit (dy)/(dx),y=arccos(4x^2) ?
The answer to implicit (dy)/(dx),y=arccos(4x^2) is (dy)/(dx)=-(8x)/(sqrt(1-16x^4))