What is the solution for (dx)/(dy)=(x^2y^2)/(1+x) ?

The solution for (dx)/(dy)=(x^2y^2)/(1+x) is x= 1/(\W((1){e^{\frac{y^3+c_{1})/3}})}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dx)/(dy)=(x^2y^2)/(1+x)

\frac{d x}{d y} = \frac{x ^{2} y ^{2}}{1 + x}

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

Solution steps

\frac{d x}{d y} = \frac{x ^{2} y ^{2}}{1 + x}

Solve separable ODE:

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

x = \frac{1}{W ( \frac{1}{e ^{\frac{y ^{3} + c _{1}}{3}}} )}

What is the solution for (dx)/(dy)=(x^2y^2)/(1+x) ?
The solution for (dx)/(dy)=(x^2y^2)/(1+x) is x= 1/(\W((1){e^{\frac{y^3+c_{1})/3}})}