What is the solution for (dy)/(dt)=e^{-2t+3y} ?

The solution for (dy)/(dt)=e^{-2t+3y} is y=-(ln(3/2 e^{-2t}-c_{1}))/3

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(dy)/(dt)=e^{-2t+3y}

\frac{d y}{d t} = e^{- 2 t + 3 y}

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

Solution steps

\frac{d y}{d t} = e^{- 2 t + 3 y}

Solve separable ODE:

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

What is the solution for (dy)/(dt)=e^{-2t+3y} ?
The solution for (dy)/(dt)=e^{-2t+3y} is y=-(ln(3/2 e^{-2t}-c_{1}))/3