What is laplacetransform 4sin(2t) ?

The answer to laplacetransform 4sin(2t) is 8/(s^2+4)

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laplacetransform 4sin(2t)

laplace transform

4 sin (2 t)

\frac{8}{s ^{2} + 4}

Solution steps

L {4 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= 4 \cdot \frac{2}{s ^{2} + 4}

Refine

4 \frac{2}{s ^{2} + 4} : \frac{8}{s ^{2} + 4}

= \frac{8}{s ^{2} + 4}

What is laplacetransform 4sin(2t) ?
The answer to laplacetransform 4sin(2t) is 8/(s^2+4)