What is the integral of (x^5+x-1)/(x^3+1) ?

The integral of (x^5+x-1)/(x^3+1) is (x^3)/3-ln|x+1|+C

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integral of (x^5+x-1)/(x^3+1)

\int \frac{x ^{5} + x - 1}{x ^{3} + 1} d x

\frac{x ^{3}}{3} - ln ∣ x + 1 ∣ + C

Solution steps

\int \frac{x ^{5} + x - 1}{x ^{3} + 1} d x

Long division

\frac{x ^{5} + x - 1}{x ^{3} + 1} : x^{2} - \frac{1}{x + 1}

= \int x^{2} - \frac{1}{x + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int \frac{1}{x + 1} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

= \frac{x ^{3}}{3} - ln ∣ x + 1 ∣

Add a constant to the solution

= \frac{x ^{3}}{3} - ln ∣ x + 1 ∣ + C

What is the integral of (x^5+x-1)/(x^3+1) ?
The integral of (x^5+x-1)/(x^3+1) is (x^3)/3-ln|x+1|+C