What is implicit (dy)/(dx),x^2+y^2=0 ?

The answer to implicit (dy)/(dx),x^2+y^2=0 is (dy)/(dx)=-x/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

implicit (dy)/(dx),x^2+y^2=0

implicit derivative

\frac{d y}{d x}, x^{2} + y^{2} = 0

\frac{d y}{d x} = - \frac{x}{y}

Solution steps

x^{2} + y^{2} = 0

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x}{y}

\frac{d y}{d x} = - \frac{x}{y}

What is implicit (dy)/(dx),x^2+y^2=0 ?
The answer to implicit (dy)/(dx),x^2+y^2=0 is (dy)/(dx)=-x/y