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Popular Calculus >

integral of 2z^5e^{1-z}

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Solution

∫2z5e1−zdz

Solution

2e(−e−zz5−5(e−zz4−4(−e−zz3−3(e−zz2−2(−e−zz−e−z)))))+C
Solution steps
∫2z5e1−zdz
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=2⋅∫z5e1−zdz
z5e1−z=e1z5e−z=2⋅∫e1z5e−zdz
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=2e1⋅∫z5e−zdz
Simplify=2e⋅∫z5e−zdz
Apply u-substitution
=2e⋅∫euu5du
Apply Integration By Parts
=2e(u5eu−∫5u4eudu)
∫5u4eudu=5(u4eu−4(u3eu−3(u2eu−2(euu−eu))))
=2e(u5eu−5(u4eu−4(u3eu−3(u2eu−2(euu−eu)))))
Substitute back u=−z=2e((−z)5e−z−5((−z)4e−z−4((−z)3e−z−3((−z)2e−z−2(e−z(−z)−e−z)))))
Simplify 2e((−z)5e−z−5((−z)4e−z−4((−z)3e−z−3((−z)2e−z−2(e−z(−z)−e−z))))):2e(−e−zz5−5(e−zz4−4(−e−zz3−3(e−zz2−2(−e−zz−e−z)))))
=2e(−e−zz5−5(e−zz4−4(−e−zz3−3(e−zz2−2(−e−zz−e−z)))))
Add a constant to the solution=2e(−e−zz5−5(e−zz4−4(−e−zz3−3(e−zz2−2(−e−zz−e−z)))))+C

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