What is area y=e^{3x},y=e^{-3x},x=-1 ?

The answer to area y=e^{3x},y=e^{-3x},x=-1 is (e^6-2e^3+1)/(3e^3)

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area y=e^{3x},y=e^{-3x},x=-1

area

y = e^{3 x}, y = e^{- 3 x}, x = - 1

\frac{e ^{6} - 2 e ^{3} + 1}{3 e ^{3}}

Decimal

6.04510 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{0} e^{3 x} - e^{- 3 x} d x

Solve

\int_{- 1}^{0} e^{3 x} - e^{- 3 x} d x : \frac{e ^{6} - 2 e ^{3} + 1}{3 e ^{3}}

The area is:

= \frac{e ^{6} - 2 e ^{3} + 1}{3 e ^{3}}

What is area y=e^{3x},y=e^{-3x},x=-1 ?
The answer to area y=e^{3x},y=e^{-3x},x=-1 is (e^6-2e^3+1)/(3e^3)