What is the integral from 0 to 1 of pi(4x)^2 ?

The integral from 0 to 1 of pi(4x)^2 is (16pi)/3

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integral from 0 to 1 of pi(4x)^2

\int_{0}^{1} π (4 x)^{2} d x

\frac{16 π}{3}

Decimal

16.75516 \dots

Solution steps

\int_{0}^{1} π (4 x)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{1} (4 x)^{2} d x

Simplify

(4 x)^{2} : 16 x^{2}

= π \cdot \int_{0}^{1} 16 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π 16 \cdot \int_{0}^{1} x^{2} d x

Apply the Power Rule

= π 16 [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= π 16 \cdot \frac{1}{3}

Simplify

= \frac{16 π}{3}

What is the integral from 0 to 1 of pi(4x)^2 ?
The integral from 0 to 1 of pi(4x)^2 is (16pi)/3