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Popular Calculus >

y^'+2ty=t

Solution

y^{^{'}} + 2 t y = t

Solution

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{1}{2}

Solution steps

y^{'} (t) + 2 t y = t

Solve separable ODE:

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{1}{2}

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2ty=t ?
The solution for y^'+2ty=t is y=(e^{-t^2+c_{1}})/2+1/2