What is the derivative of-16ax^2+a+1/3 ?

The derivative of-16ax^2+a+1/3 is -32ax

What is the first derivative of-16ax^2+a+1/3 ?

The first derivative of-16ax^2+a+1/3 is -32ax

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\frac{d}{d x} (- 16 a x^{2} + a + \frac{1}{3})

- 32 a x

Solution steps

\frac{d}{d x} (- 16 a x^{2} + a + \frac{1}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (16 a x^{2}) + \frac{d a}{d x} + \frac{d}{d x} (\frac{1}{3})

\frac{d}{d x} (16 a x^{2}) = 32 a x

\frac{d a}{d x} = 0

\frac{d}{d x} (\frac{1}{3}) = 0

= - 32 a x + 0 + 0

Simplify

= - 32 a x

What is the derivative of-16ax^2+a+1/3 ?
The derivative of-16ax^2+a+1/3 is -32ax
What is the first derivative of-16ax^2+a+1/3 ?
The first derivative of-16ax^2+a+1/3 is -32ax