What is the integral of (4x^3-3x^2+5) ?

The integral of (4x^3-3x^2+5) is x^4-x^3+5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (4x^3-3x^2+5)

\int (4 x^{3} - 3 x^{2} + 5) d x

x^{4} - x^{3} + 5 x + C

Solution steps

\int 4 x^{3} - 3 x^{2} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x - \int 3 x^{2} d x + \int 5 d x

\int 4 x^{3} d x = x^{4}

\int 3 x^{2} d x = x^{3}

\int 5 d x = 5 x

= x^{4} - x^{3} + 5 x

Add a constant to the solution

= x^{4} - x^{3} + 5 x + C

What is the integral of (4x^3-3x^2+5) ?
The integral of (4x^3-3x^2+5) is x^4-x^3+5x+C