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Beliebt Rechnen >

y^'=2t,y(0)=1

Lösung

y^{^{'}} = 2 t, y (0) = 1

Lösung

y = t^{2} + 1

Schritte zur Lösung

y^{'} (t) = 2 t

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 2 t d t

\int 2 t d t = t^{2} + c_{1}

y = t^{2} + c_{1}

Wende die Anfangsbedingung an:

y = t^{2} + 1

y = t^{2} + 1

Graph

Beliebte Beispiele

integral of (2x)/((x^2+x+1))

y^'=(3x^7e^{y/x}+x^5y^2)/(x^6y)

limit as x approaches 2 of (x-7)/(x+3)

integral from 1 to infinity of 1/(x^3-1)

integral of ysqrt(x+y^2)