What is the derivative of (x^2+1^8) ?

The derivative of (x^2+1^8) is 16x(x^2+1)^7

What is the first derivative of (x^2+1^8) ?

The first derivative of (x^2+1^8) is 16x(x^2+1)^7

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\frac{d}{d x} ((x^{2} + 1)^{8})

16 x (x^{2} + 1)^{7}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{8})

Apply the chain rule:

8 (x^{2} + 1)^{7} \frac{d}{d x} (x^{2} + 1)

= 8 (x^{2} + 1)^{7} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 8 (x^{2} + 1)^{7} \cdot 2 x

Simplify

= 16 x (x^{2} + 1)^{7}

What is the derivative of (x^2+1^8) ?
The derivative of (x^2+1^8) is 16x(x^2+1)^7
What is the first derivative of (x^2+1^8) ?
The first derivative of (x^2+1^8) is 16x(x^2+1)^7