integral from 0 to 8 of 2t^2-24t+70

Lösung

\int_{0}^{8} 2 t^{2} - 24 t + 70 d t

\frac{400}{3}

Dezimale

133.33333 \dots

Schritte zur Lösung

\int_{0}^{8} 2 t^{2} - 24 t + 70 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 2 t^{2} d t - \int_{0}^{8} 24 t d t + \int_{0}^{8} 70 d t

\int_{0}^{8} 2 t^{2} d t = \frac{1024}{3}

\int_{0}^{8} 24 t d t = 768

\int_{0}^{8} 70 d t = 560

= \frac{1024}{3} - 768 + 560

Vereinfache

\frac{1024}{3} - 768 + 560 : \frac{400}{3}

= \frac{400}{3}

y^{^{'}} = \frac{1 + y ^{2}}{1 + x ^{2}}

\int \frac{1}{s ^{2}} d s

x \to - 1 lim (\frac{x - 1}{x ^{2} - 1})

\int_{1}^{2.5} e^{- x} d x

\frac{d}{d x} (\frac{x ^{2} - 2 x + 1}{x + 1})