What is the tangent of f(x)=(x^3)/4 ,\at x=-6 ?

The tangent of f(x)=(x^3)/4 ,\at x=-6 is y=27x+108

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tangent of f(x)=(x^3)/4 ,\at x=-6

tangent of

f (x) = \frac{x ^{3}}{4}, at x = - 6

y = 27 x + 108

Solution steps

Find the tangent point:

(- 6, - 54)

Find the slope of

f (x) = \frac{x ^{3}}{4} : \frac{df ( x )}{d x} = \frac{3 x ^{2}}{4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 27

Find the line with slope m=

27

and passing through

(- 6, - 54) : y = 27 x + 108

y = 27 x + 108

What is the tangent of f(x)=(x^3)/4 ,\at x=-6 ?
The tangent of f(x)=(x^3)/4 ,\at x=-6 is y=27x+108