What is the solution for y^'-2ty=12t^2e^{t^2},y(0)=5 ?

The solution for y^'-2ty=12t^2e^{t^2},y(0)=5 is y=4e^{t^2}t^3+5e^{t^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'-2ty=12t^2e^{t^2},y(0)=5

y^{^{'}} - 2 t y = 12 t^{2} e^{t^{2}}, y (0) = 5

y = 4 e^{t^{2}} t^{3} + 5 e^{t^{2}}

Solution steps

y^{'} (t) - 2 t y = 12 t^{2} e^{t^{2}}

Solve linear ODE:

y = 4 e^{t^{2}} t^{3} + 5 e^{t^{2}}

y = 4 e^{t^{2}} t^{3} + 5 e^{t^{2}}

What is the solution for y^'-2ty=12t^2e^{t^2},y(0)=5 ?
The solution for y^'-2ty=12t^2e^{t^2},y(0)=5 is y=4e^{t^2}t^3+5e^{t^2}