What is the solution for y^'-0.4y=29sin(x) ?

The solution for y^'-0.4y=29sin(x) is y=-29(0.86206…cos(x)+0.34482…sin(x))+c_{1}e^{0.4x}

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y^'-0.4y=29sin(x)

y^{^{'}} - 0.4 y = 29 sin (x)

y = - 29 (0.86206 \dots cos (x) + 0.34482 \dots sin (x)) + c_{1} e^{0.4 x}

Solution steps

y^{'} (x) - 0.4 y = 29 sin (x)

Solve linear ODE:

y = - 29 (0.86206 \dots cos (x) + 0.34482 \dots sin (x)) + c_{1} e^{0.4 x}

y = - 29 (0.86206 \dots cos (x) + 0.34482 \dots sin (x)) + c_{1} e^{0.4 x}

What is the solution for y^'-0.4y=29sin(x) ?
The solution for y^'-0.4y=29sin(x) is y=-29(0.86206…cos(x)+0.34482…sin(x))+c_{1}e^{0.4x}