What is the tangent of f(x)=x^2+9,(-2,13) ?

The tangent of f(x)=x^2+9,(-2,13) is y=-4x+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=x^2+9,(-2,13)

tangent of

f (x) = x^{2} + 9, (- 2, 13)

y = - 4 x + 5

Solution steps

Find the slope of

f (x) = x^{2} + 9 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, 13) : y = - 4 x + 5

y = - 4 x + 5

What is the tangent of f(x)=x^2+9,(-2,13) ?
The tangent of f(x)=x^2+9,(-2,13) is y=-4x+5