What is the integral of pitcos(nt) ?

The integral of pitcos(nt) is pi/(n^2)(ntsin(nt)+cos(nt))+C

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integral of pitcos(nt)

\int π t cos (n t) d t

\frac{π}{n ^{2}} (n t sin (n t) + cos (n t)) + C

Solution steps

\int π t cos (n t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int t cos (n t) d t

Apply u-substitution

= π \cdot \int \frac{u cos ( u )}{n ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \frac{1}{n ^{2}} \cdot \int u cos (u) d u

Apply Integration By Parts

= π \frac{1}{n ^{2}} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= π \frac{1}{n ^{2}} (u sin (u) - (- cos (u)))

Substitute back

u = n t

= π \frac{1}{n ^{2}} (n t sin (n t) - (- cos (n t)))

Simplify

π \frac{1}{n ^{2}} (n t sin (n t) - (- cos (n t))) : \frac{π}{n ^{2}} (n t sin (n t) + cos (n t))

= \frac{π}{n ^{2}} (n t sin (n t) + cos (n t))

Add a constant to the solution

= \frac{π}{n ^{2}} (n t sin (n t) + cos (n t)) + C

What is the integral of pitcos(nt) ?
The integral of pitcos(nt) is pi/(n^2)(ntsin(nt)+cos(nt))+C