What is the tangent of f(x)=6-x^2,\at x=7 ?

The tangent of f(x)=6-x^2,\at x=7 is y=-14x+55

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=6-x^2,\at x=7

tangent of

f (x) = 6 - x^{2}, at x = 7

y = - 14 x + 55

Solution steps

Find the tangent point:

(7, - 43)

Find the slope of

f (x) = 6 - x^{2} : \frac{df ( x )}{d x} = - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 14

Find the line with slope m=

- 14

and passing through

(7, - 43) : y = - 14 x + 55

y = - 14 x + 55

What is the tangent of f(x)=6-x^2,\at x=7 ?
The tangent of f(x)=6-x^2,\at x=7 is y=-14x+55