What is the solution for y^'= x/(18y) ?

The solution for y^'= x/(18y) is y=(sqrt(c_{1)+x^2})/(3sqrt(2)),y=-(sqrt(c_{1)+x^2})/(3sqrt(2))

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y^'= x/(18y)

y^{^{'}} = \frac{x}{18 y}

y = \frac{c _{1} + x ^{2}}{3 2}, y = - \frac{c _{1} + x ^{2}}{3 2}

Solution steps

y^{'} (x) = \frac{x}{18 y}

Solve separable ODE:

y = \frac{c _{1} + x ^{2}}{3 2}, y = - \frac{c _{1} + x ^{2}}{3 2}

y = \frac{c _{1} + x ^{2}}{3 2}, y = - \frac{c _{1} + x ^{2}}{3 2}

What is the solution for y^'= x/(18y) ?
The solution for y^'= x/(18y) is y=(sqrt(c_{1)+x^2})/(3sqrt(2)),y=-(sqrt(c_{1)+x^2})/(3sqrt(2))