What is the d/(dt)(1/((t+1)^2)) ?

The d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)

What is the first d/(dt)(1/((t+1)^2)) ?

The first d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)

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\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

- \frac{2}{( t + 1 ) ^{3}}

Solution steps

\frac{d}{d t} (\frac{1}{( t + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((t + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( t + 1 ) ^{3}} \frac{d}{d t} (t + 1)

= - \frac{2}{( t + 1 ) ^{3}} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= - \frac{2}{( t + 1 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( t + 1 ) ^{3}}

What is the d/(dt)(1/((t+1)^2)) ?
The d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)
What is the first d/(dt)(1/((t+1)^2)) ?
The first d/(dt)(1/((t+1)^2)) is -2/((t+1)^3)