What is the derivative of x^2+3x+14 ?

The derivative of x^2+3x+14 is 2x+3

What is the first derivative of x^2+3x+14 ?

The first derivative of x^2+3x+14 is 2x+3

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derivative of

x^{2} + 3 x + 14

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 14)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (14)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (14) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

What is the derivative of x^2+3x+14 ?
The derivative of x^2+3x+14 is 2x+3
What is the first derivative of x^2+3x+14 ?
The first derivative of x^2+3x+14 is 2x+3