y^{''}-10y^'+y=0

Lösung

y^{^{''}} - 10 y^{^{'}} + y = 0

y = c_{1} e^{(5 + 26) t} + c_{2} e^{(5 - 26) t}

Schritte zur Lösung

y^{''} (t) - 10 y^{'} (t) + y = 0

Solve linear ODE:

y = c_{1} e^{(5 + 26) t} + c_{2} e^{(5 - 26) t}

y = c_{1} e^{(5 + 26) t} + c_{2} e^{(5 - 26) t}

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