derivative p(t)=5e^{0.0278t}

解

導関数

p (t) = 5 e^{0.0278 t}

0.139 e^{0.0278 t}

解答ステップ

\frac{d}{d t} (5 e^{0.0278 t})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (e^{0.0278 t})

連鎖法則を適用:

e^{0.0278 t} \frac{d}{d t} (0.0278 t)

= e^{0.0278 t} \frac{d}{d t} (0.0278 t)

\frac{d}{d t} (0.0278 t) = 0.0278

= 5 e^{0.0278 t} \cdot 0.0278

簡素化

= 0.139 e^{0.0278 t}