What is (d^2)/(dx^2)((x^2-4x)/(x+1)) ?

The answer to (d^2)/(dx^2)((x^2-4x)/(x+1)) is (10)/((x+1)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(d^2)/(dx^2)((x^2-4x)/(x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 4 x}{x + 1})

\frac{10}{( x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 4 x}{x + 1})

\frac{d}{d x} (\frac{x ^{2} - 4 x}{x + 1}) = \frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}})

\frac{d}{d x} (\frac{x ^{2} + 2 x - 4}{( x + 1 ) ^{2}}) = \frac{10}{( x + 1 ) ^{3}}

= \frac{10}{( x + 1 ) ^{3}}

What is (d^2)/(dx^2)((x^2-4x)/(x+1)) ?
The answer to (d^2)/(dx^2)((x^2-4x)/(x+1)) is (10)/((x+1)^3)