What is the tangent of y=x^2+7,(-4,23) ?

The tangent of y=x^2+7,(-4,23) is y=-8x-9

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tangent of y=x^2+7,(-4,23)

tangent of

y = x^{2} + 7, (- 4, 23)

y = - 8 x - 9

Solution steps

Find the slope of

y = x^{2} + 7 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 23) : y = - 8 x - 9

y = - 8 x - 9

What is the tangent of y=x^2+7,(-4,23) ?
The tangent of y=x^2+7,(-4,23) is y=-8x-9