What is the tangent of f(x)= 1/(x^4),(-2, 1/16) ?

The tangent of f(x)= 1/(x^4),(-2, 1/16) is y= 1/8 x+5/16

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tangent of f(x)= 1/(x^4),(-2, 1/16)

tangent of

f (x) = \frac{1}{x ^{4}}, (- 2, \frac{1}{16})

y = \frac{1}{8} x + \frac{5}{16}

Solution steps

Find the slope of

f (x) = \frac{1}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{5}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(- 2, \frac{1}{16}) : y = \frac{1}{8} x + \frac{5}{16}

y = \frac{1}{8} x + \frac{5}{16}

What is the tangent of f(x)= 1/(x^4),(-2, 1/16) ?
The tangent of f(x)= 1/(x^4),(-2, 1/16) is y= 1/8 x+5/16